3.5 Why does a quantum mechanical state change?

Since all Eigenstates of the Hamiltonian are stable, one needs at least a short perturbation of the system to get an excited state; e.g.:

For all these processes according to Eq. (3.18) the transfer matrix element can be calculated; they quantize the probability for these transitions.
The excited state may loose energy by the same processes as described above:

REMARK: Principally you do not need superconductivity to find zero ohmic resistance; once a current flow started (described by the \(k\)-distribution of electrons, which are Eigenstates of the Hamiltonian) it would be stable for infinite time. You need defects within the crystal or phonons to reduce the current by scattering.
For every well defined measurement and if knowing the underlying processes, quantum mechanics provides the adequate calculation rule.

  1. Which is the starting state?

  2. Which is the end state?

  3. Which expectation value do I have to calculate?

Examples:
Scattering experiment:

  1. incoming free particle

  2. outgoing free particle

  3. Scattering cross section

Recombination processes:

  1. State in the first band

  2. State in the second band

  3. Cross section of a trap (a surface)/Probability for a radiative transition


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© J. Carstensen (Quantum Mech.)