11.5 Wootz Swords | ||||||||||
11.5.1 The Winner is.... | ||||||||||
What It's All About | ||||||||||
Wootz swords in my terminology are swords that
were
So let's recall what it is all about. The short version is here. |
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The big question was (and is): | ||||||||||
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The way I put it the emphasize is on "nice", and that is not a good
scientific word because it is hard to attach a number measuring the degree of nicety. It is just as hard to define what
separates a nice wootz pattern from a run-of-the-mill one, as it is to define what separates
pornography from art. Yet you just know it when you see it. Below are nice wootz patterns; here are a few more | ||||||||||
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You only see the pattern after the (polished) blade has been properly etched.
True connoisseurs have with little success tried to classify "nice" in more detail; consult the illustration module if you must know. In essence one distinguishes:
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In the crucible steel
chapter I have given you already a lot of information about wootz steel; now is a good time to refresh your memory.
Having you back, I propose that you now make a wootz sword with a nice pattern. You started out as a smith already in chapter 2, after all. By now you are a smith in chapter 11 and you have learnt a lot about iron and steel in the meantime. Let's see if all that knowledge allows you to do the job. It shouldn't be all that difficult because several modern smiths are at it right now - and some have succeeded. I'm going to help a bit, though. Le's start by working our way back and see if we can figure out what it takes to make a wootz sword. Generating the process recipe will also bring out the still open questions and allow us to focus on what, exactly, all the jousting is about. So what do we know "for sure" about the making of wootz swords? |
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First of all we do know what causes the pattern, the interlaced
dark and bright regions on the blade. The "color" reflects the difference in the cementite concentration or, being
a bit more precise, the difference in the concentration of largish cementite precipitates.
You must etch your blade a bit to make this difference visible but this is a relatively trivial (if sometimes frustrating)
part of the recipe and we will not discus the various techniques for that. Looking at the blades above with a microscope at medium magnification (around 100x) will give pictures like these: | ||||||||||
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So let's ask a simple first question. We know that one needs high-carbon steel
for wootz patterns. So just how much carbon do we need to form sufficient
cementite for forming the pattern? Let's start by considering how much cementite is actually there "to see" in a steel sample with, to make it easy, |
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From Carbon to Cementite | ||||||
In order to keep things simple we envision a 100 g (or 100 pound or 100 ton)
cube of carbon steel. If 1 % of the weight comes
from the carbon in there, we have 99 grams of iron and 1 gram of carbon, obviously. The carbon will eventually turn into cementite, Fe3C. Any carbon atom thus takes three iron atoms away, and that means you have less iron now. I know it is a bit confusing because you still have the same number of iron atoms in the cube. But an iron atom contained in cementite is not part of an iron crystal (ferrite at room temperature) anymore, just as an oxygen atom in a water molecule is not part of the air anymore. Now to the big question: How much room does the cementite occupy in our cube? And what could we "see" by looking at the cube? Simple questions but the answers take quite a bit of thought. We need to keep track of atom counts now and in order to do that we first need to go to atomic concentrations. I gave you a whole module dealing with that, and you can look up there how it is done. Or just believe me: 1 wt% of carbon corresponds to 4.81 at% of carbon. That means that from all the atoms in our 100 grams of steel 4.81 % are carbon atoms, and 95.19 % are iron atoms. | ||||||
Now imagine a smaller cube containing 9.519 iron atoms and and 481 carbon atoms
and you get the right relation. Altogether we have 9.519 + 481=10.000 atoms (surprise?). Now we form cementite. Our 481 carbon atoms will need 3 × 481=1443 iron atoms to form one molecule of cementite, Fe3C. That means we have only 9.519 - 1443=8.076 iron atoms left for being iron. Relative to the 10.000 atoms we started with this equals 80.76 at% and the rest, 19.24 % of all the atoms in the cube, are now in the cementite! That's what just 1 wt % of carbon will do! With 6.7 wt% carbon only cementite would be left I'll illustrate that with a very simple picture:4) |
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The small blue cubes in the upper part of the picture just visualize the percentages. The big cube demonstrates what you could get by breaking up the solid block of cementite. First look a the right hand side. The grey part corresponds to the volume the cementite takes up if it would be in one block. Now consider that block as being built up by rods, e.g. three abreast as shown on top. Now break one rod into cubes and just leave every other cube in place. Than you can pack six rows of interrupted cubes into your crystal replacing the three full rods shown. Continue on the next level and you have the structure on the left-hand side of the big cube above. |
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What seems to become clear is that you can make a lot of rather big cementite particles this way, or a hell of a lot of smaller ones - from just 1 wt% of carbon! With some special arrangement of all these precipitates you should be able to produce a pattern. | ||||||
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You don't see it? Then look at the phase diagram. Or just believe me when I remind you that with the first 0.76 wt% of carbon you simply form pearlite . A cube of just 0,76 wt% steel would simply consist of pearlite grains, i.e. grains "filled" with the by now well-known "zebra" structure. Of course, part of the "zebra" are the cementite lamellae but everything is so small (around or below the 1 µm region) that you simply cannot see any pattern on a pearlite surface, not to mention a "nice" one. The cementite in the pearlite is effectively invisible to us and the only optical effect is the "pearl-like luster". | ||||||
In our 1 wt% example we have only 0.24 wt% carbon left to form some extra cementite
but that might not be enough for forming visible cementite. For the formation of a nice wootz pattern we need cementite in excess of the one in the pearlite, and this means that we need to go well above the eutectoid 0.76 wt% carbon concentration. So let's take 1.76 wt% and we are right back to the picture above (with the "blue" in the cube now denoting pearlite). Incidentally, that's a typical carbon concentration for crucible steel and wootz swords. |
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Getting High Carbon Steel | ||
Now we know what we need: a sufficient amount of about 2 wt% carbon steel, i.e. ultra-high carbon steel (UHCS). Where should you look for that before 1800 or so? It's a tough assignment - even for the time traveler who knows all about steel. For an ancient European smith it was almost impossible to get UHCS. If you followed me you know by now that all the bloomeries of old did not just produce wrought iron but all kinds of carbon (and phosphorous) steel, up to and including cast iron. However, 2 wt% of carbon is difficult to make in a bloomery. It is too much carbon for a regular solid state bloomery process (look at this picture to refresh your memory). If you would try to smelt 2 % C UHCS in a bloomery, you would quite likely run into the other extreme and end up with cast iron, getting carbon concentrations that are too large. | ||
Europeans thus couldn't easily have forged wootz swords - they lacked the raw material. | ||
Smart Indians or Iranians, on the other hand, employed a crucible process after
smelting raw iron / steel in a bloomery and made UHCS conscientiously. No, they did
not! They did not produce steel with about 2 wt% carbon intentionally
, they produced it by default. They would for sure have preferred to make 0.7 wt% steel but couldn't because their process
was temperature limited. If everything worked, the resulting wootz or bulat cake was liquid once with a bit of liquid slag on top. Cooling down solidified the steel without incorporating the slag. This made crucible steel superior to bloomery steel with respect to slag inclusions. |
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Of course, crucible steel was not pure high-carbon steel and it was not always "perfect" either. It contained the usual impurities, e.g. phosphorous, depending on what was contained in the ingredients. There seems to be some evidence that the stuff wasn't always completely molten either, just what one would suspect. The resulting cake then was rather inhomogeneous. | ||
But let's go on. Let's assume that you, the ancient smith, did get into possession
of a good wootz cake with the required | ||
Shaping the Cementite | ||||||||||
You now have a 2 wt% carbon steel that will produce sufficient cementite for pattern
formation. But you, like all of us, know that during cooling the cementite forming first (the "primary
cementite") will tend to line the grain boundaries
, and that the resulting steel is completely brittle and thus almost useless for swords
- but not for many other things like punches or dies for wire
drawing. I'm saying "almost" useless since the famed Ulfberht swords, if indeed made from crucible steel,
would fall into that category. Why they might have been perceived as very good is not so clear; I have already made some comments to that. Somebody, sometime (maybe around 500 AD) and somewhere (in India or thereabouts) ran across the first major trick that needs to be employed to avoid this: |
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Produce little "spheres" or just pebble-like particles or precipitates instead of shells around grains, long needles (look up "Widmanstätten") or anything spreading in some direction. The process for doing this is called "spheroidization ". | ||||||||||
I already gave you a list of how that can be done. Read up on it; here I only emphasize the major points:
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Whatever you did to get your cementite to ball up - after that has happened the second major trick comes into play: | ||||||||||
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You must never ever again raise the temperature to well above the A1 temperature of 727 oC (1341 oF) where ferrite changes to austenite! If you do, a lot of the spheroidized cementite will dissolve and chances are that it precipitates in unwanted shapes during cooling. A little bit above A1 for a short time - OK. But never a lot above A1 or for long times! | ||||||||||
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The smith just must be acutely aware of all of that. An ancient European smith
who by accident got hold of some crucible steel was not likely to find that out by playing around a bit with the stuff.
Western 18th and 19th century smiths indeed didn't get it according to some sources. Since this is not something you find out yourself, getting in possession of some crucible steel just couldn't do much good in the "West". In contrast, the ancient smiths in India and Persia knew what to do 1600 years or so ago. They did make blades from crucible UHCS that contain spheroidized cementite and are no longer brittle. The link shows what that looks like. Did you believe that? You sucker! The link shows what modern scientists ( O. D. Sherby and J. Wadsworth, actually) can do with modern methods and knowledge. The theory, though a bit involved, is also well-known by now 1), not to mention that times, temperatures and impurity content are known and controlled. The question is: Did the really old smiths working with crucible steel produce spheroidized cementite? | ||||||||||
I have yet to see a micrograph of old
crucible steel that shows spheroidized cementite. In contrast, I (and you) have seen structures that show what we want
to avoid: grain boundaries solidly encased in cementite. Just look at the picture
of the "Stuttgart" Ulfberht sword that as been made from crucible steel according to Alan
Williams. "But what about the pictures up there", you might say. "Don't they show spheroidized cementite in bands?" Yes, they do. But these pictures are from much later wootz blades with a pattern and we aren't there yet. Moreover, the steel has been etched in a way to bring out the wootz pattern and not to show the structure. You just do not know in these cases what you do not see because of the undefined etching. |
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What we would need to see at this stage are metallographic examinations of crucible
steel blades that do not show a water pattern. Alan Williams in his book about Ulfberht
swords supplies quite a few pictures of that - and not one of these pictures shows good spheroidization! There are certainly more metallographic investigations into the structure of old crucible steel, and I do not know them all. From what I know I show you one example: | ||||||||||
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The sample origin is a bit unclear. It's probably 19th or 18th century, it is
certainly not ancient. We see several remarkable things:
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At this point we simply learn that not all crucible steel swords are born
equal. If everything worked and the cementite is nicely spheroidized everywhere, these blades were very hard throughout
but not brittle. But rather brittle blades must have been made, too, as well as blades given to cold shortness, inhomogeneous
blades and whatever else results if not everything is "just right" in the production of the blade. The picture below shows a small section of an otherwise magnificent wootz tulwar where the pattern is not present in parts: | ||||||||||
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Did something go wrong during the forging of this wootz blade? Well, yes - but in a peculiar way: | ||||||||||
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As I learned just recently (fall 2017), this blade has a core of regular non-wootz steel with a thin layer of wootz steel laminated to both sides. In the "defective" area, this thin wootz layer has been polished off. More to that in the link given above. | ||||||||||
Now let's assume that you managed to forge a blade that contains nicely spheroidized cementite. Now we come to the key question: | ||||||||||
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A pattern or no pattern? This is the question. Then we have follow-up questions:
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Forming a Pattern You Can See - Some Basics | ||||||||||
We want to make a nice clearly visible pattern. The first question in this context is: What can you see and what is invisible? Not an easy question. With proper light, you can see a single hair. A hair is about 30 µm (=0.03 mm) thick but pretty long. Could you see a 30 µm diameter cementite sphere, cut in half and embedded in featureless "polished" iron? (Left hand picture below). Probably just so, as a tiny speck under certain good illumination condition. Illumination is important; at night you can't see all that much after all. So let's assume that you have always the best illumination to keep the subject simple. | ||||||||||
Could you see a lot of (cut
in half) 30 µm or so cementite spheres that are uniformly distributed in a (polished) iron matrix? (Middle picture
below) No, you can't. You cannot "see" all the individual particles. A polished sample after etching might look darker and bit motley compared to a pure iron sample - but that's it. You only "see" something if the cementite is distributed in a non-uniform way in some kind of banding (right hand picture below). Here is my not very good attempt to illustrate all of this in a very schematic way: | ||||||||||
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Note that we need at least four parameters to describe the banded
structure in the upper right-hand corner:
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Are there any rules of thumb for those parameters? Yes - all you need to do is to look at the pictures above or the one right below. They show microscopic cementite particle distributions that do produce a clear pattern: | ||||||||||
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We "see" that a distance between the bands of around 50 µm on the blade is fine, and that particle sizes around 5 µm are fine, too - provided there are a lot! Average distances between particles in a band should obviously be small, well below 5 µm. In three dimensions we have parallel sheets or bands of cementite particles, of course. Since the surface intersects those bands at a small angle, the distance between the bands will be considerably larger there; look at the picture below or this module to see that. | ||||||||||
Now we have a good idea of what we need to make: | ||||||||||
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We knew that all along, of course. But now we know also some numbers - and that is a very valuable asset. | ||||||||||
We know now, for example, that we need not only to spheroidize our cementite,
we need to do it in a way where we get a high density of particles with a diameter of several µm. If we do that and
distribute these particles uniformly in the blade, we will not
get a visible pattern. If we distribute them in well-defined layers about 50 µm apart, we will be able to produce nice patterns on the blade. How about something in between? Not a uniform distribution, but no well-defined layered structure either? That might also produce a pattern - but not necessarily a "nice" one! |
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We are getting closer to what the fight is all about. Simplified, the Wadsworth group maintains that it is relatively easy to get patterns with just about any UHCS steel, including old-fashioned crucible steel, by following a few simple rules: | ||||||||||
We might not rate it as a "nice" pattern but then we have only bad copies of the original pictures that do not show details of the structure. It is certainly as good as the one shown by the Wadsworth group. |
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Käthe Harnecker and possibly the Wadsworth group, however, did not yet include another key ingredient into their recipe, the third major trick: Cyclingthe temperature just around the A1 transformation temperature. This will tend to make the cementite particles larger and the size distribution narrower, and the region in between precipitate bands more devoid of the stuff. | ||||||||||
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Strangely enough, I have rarely encountered this term in connection with wootz patterns. Ostwald ripening, sometimes called "particle coarsening", is a process that kills small precipitates in favor of larger ones. | ||||||||||
Start with a distribution of a lot of precipitates with all all kinds of diameters, do some
Ostwald ripening, and you are left with fewer precipitates, all of which are large - just as in the picture
above. Originally, there might have been a lot of smaller cementite particles between the bands but after some Ostwald
ripening they all have disappeared. Precipitates below a certain size shrink and the carbon they release goes to the bigger
ones so they grow. What does it take to inducing Oswald ripening? In the most simple case you just keep your sample at high temperatures for a while. If you want to be a bit more sophisticated, you use a transition temperature around which you oscillate the temperature like this: |
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Of course, everything needs to be done "just right" and there are many ways of doing it wrong. More to that in the links given. What you might get looks schematically like this: | ||||||||||
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In the microscope picture above you can see
that severe Ostwald ripening was employed. You don't see it? Consider:
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Now take some UHCS, employ all of the above, and optimize the many parameters
involved. It might produce produce a wootz pattern; maybe even a reasonably nice one.
So Wadsworth wins? Not yet! Two questions remain:
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Wadsworth and others certainly tried to answer the question implicitly contained in these two statements. I won't go into that here, however, because it is not convincing. It is more rewarding to invoke Verhoeven now. Most of his work centers on these two points. So let's see what he has to offer. | ||||||||||
Forming a Pattern You Can See - Some Possibilities | ||
How do you get cementite precipitates to agglomerate in the right geometry? Sheets
of cementite particles running roughly parallel to the blade surface at sizes and spacings
as discussed above? There are several possible answers, let me list four of them:
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Wadsworth and his followers lean to the first possibility; let's call it structure by forging. Verhoeven and his followers champion the second one, which I will call structure by dendrites for reasons you shall see shortly. | ||
Now let' s look at some basic possibilities for forming a pattern. Not yet a nice pattern, just a pattern. | ||
1. Possibility. Starting point: UHSC with cementite-encapsuled grains and some pearlite inside like in this picture. The structure is uniform. | ||||||||
All you need to do is to draw out your cake or billet with a hammer or roller. The initially "roundish" grains will deform into a longish structure. The cementite shell cannot deform since it is brittle. It will break up into small pieces that are still sitting at the grain boundary. Schematically this looks like this: | ||||||||
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In the picture above I have drawn in schematically
two cementite shells in white, and how they would end up as particles in the elongated structure. Now polish the surface, etch and look at it. What you see might look like this: | ||||||||
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The picture should look familiar; you have seen it before.
Note that I'm not claiming that the real structure shown in these pictures is exactly
what I have described, just that it looks like it. The way it
was made, however, would fit the general idea. What we have is a certain amount of alignment of cementite particles just by drawing out the material. A purely geometric effect, in other words. I wouldn't call it a nice wootz structure, however. | ||||||||
2. Possibility. Starting point: UHSC with long cementite needles all over the place, uniform distribution | ||||||||
I'm talking about a structure like this: | ||||||||
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On top is supposedly real wootz cake material with predominantly long (white) cementite needles. The picture at the bottom is from a "prill" stuck to the lid of a crucible; it features needles and grain boundary cementite. I leave open at the moment how one gets all these needles; you might also just look up the "Widmannstätten" module | ||||||||
Draw out your cake or billet with a hammer or roller once more. The initially
"roundish" grains will deform into a longish structure as before. The cementite needles will break up in shorter
needles and particles. As the grains get elongated, the needle salad will get a preferential orientation into the drawing
direction. A purely geometric effect once more. .Schematically this looks like this: |
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Sorry - I'm not an artist. The red lines just illustrate how the elongation of the grain aligns the needles that keep their relative position to some extent. Now imagine the situation in three dimensions with a higher density of needles and needle fragments. Polish the surface, etch and look at it. It might look like this: | ||||||||
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The picture should look familiar once more; you have seen it before. Note that I'm not claiming that the real structure shown in these pictures is exactly what I have described above. The way it was made, however, would fit the general idea. | ||||||||
3. Possibility. Starting point: UHSC in "cake" shape (for example a wootz cake) with cementite or strong carbide forming elements arranged in a layered or striated structure as shown: | ||||||||
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If the picture looks slightly familiar - that's because you may have seen in
in chapter 9. |
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You may now wonder how you run a crucible process in such a way hat this kind of structure evolves. The answer is: I don't know. I have made suggestions but I have no idea what, exactly one needs to do to make it work nor if it ever just happened or if it is possible at all in UHSC. I do know, however, that this kind of structure is observed in lots of other stuff that solidified from a melt. | ||||||||
And no! This has nothing to do with dendrites
and what Verhoeven proclaims about making a final striated structure in a blade - I'll get to that. Le's just assume you have a wootz cake with this structure, and that the distance between two striations is large. Then all you have to do is to draw out the cake into a blade, making sure that the cake top / bottom ends up as the sides of the blade as evident from this this simple graph: | ||||||||
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We know that the distance between the cementite sheets should
be around 50 µm and that means that the distance in the striated wootz cake should
be correspondingly larger (around 500 µm=0.5 mm, say). All you have to do is to precipitate large cementite particles in the striated structure and that isn't too difficult if you already have small cementite particles or very strong carbide formers in the desired structure. What you get after polishing / etching the surfaces might look like this in cross-section, note the "shallow angle magnification" effect: |
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Note that I'm not claiming that the real structure shown in these pictures is exactly what I have described above. The blade was actually made with the "Verhoeven
recipe" and the starting material may not have contained a striated cementite /
carbide former distribution. However, Verhoeven would have a hard time to prove that this was not the case. | ||||||||
Please note that in all three cases it is generally possible to make the structure more pronounced by employing Ostwald ripening by cycling as described above. | ||||||||
It should be clear by now that in our wootz blades we want to get the striated distribution shown right above. It allows the smith to produce the more complex patterns by manipulating the geometry of the cementite distribution during forging; I'll get to that. | ||||||||
In the third example here I have shown that a special structure in the wootz cake
or whatever starting material you use is one potential way for doing that. Now let's look at other ways, in particular Verhoeven's ideas. | ||||||||
1) | A. S. Pandit and H. K. D. H. Bhadeshia: "Divorced Pearlite in Steels", Proc. Royal Soc. A (2012) |
2) | M. R. Barnett, R. Balasubramaniam, Vinod Kumar and Colin MacRae: "Correlation between
microstructure and phosphorus segregation in a hypereutectoid Wootz steel", J Mater Sci (2009) 44:2192–2197 "The tool (=sample inevstigated) that was used in the present study was obtained from a blacksmith named Mandaloji Gangaram from the village of Konapuram, located in Kammarpalli Mandal of Nizamabad district of Northern Telangana region in Andhra Pradesh state in India. This was collected and recorded during the recent survey of Wootz steel-making sites in Medieval Telengana . This village is in very close proximity (15 km) to the famous Wootz-producing center of Konasamudram". Well. One might assume that the sample is not all that old; 19th century, maybe? |
3) | John Verhoeven and Alfred Pendray: "The Mystery of the Damascus Sword", Muse, Volume 2, Number 2 (1998) pp. 35 - 43 |
4) | Yes, you purists out there, you are right. I should have considered the volume change too, the fact that 1 atom of carbon and 3 atoms of iron in cementite occupy a volume somewhat different from that those 4 atoms take up in pure iron with the carbon atomically dissolved. Forget it! |
© H. Föll (Iron, Steel and Swords script)