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The optical efficiency hopt is easy
to understand by looking a the mechanisms that prevent photons from leaving the device. We have two basic mechanisms: |
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1. The photon is absorbed before arriving
at a (possibly internal) surface of the device. |
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2. The photon makes it to the (internal) surface of the device, but is reflected
back into the interior and then absorbed. |
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We thus have to worry about absorption of light in semiconductors in general and about reflections at surfaces. |
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The first topic is a science in itself. Here we only note a few of the major points: |
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In direct analogy to the various modes of radiative recombination, we have the
reverse process, too: A photon creates an electron hole pair occupying some levels (including, e.g. exciton levels). |
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All the conservation laws must be obeyed; phonons or other third particles (in the general
sense; some defects might come in handy here) may have to assist the process. |
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The dominating absorption process usually is the direct band–band process, i.e., straight
up in a (reduced) band diagram from an (occupied) position in the valence band to an (unoccupied) position in the conduction
band. (For indirect semiconductors this requires a larger energy than the band gap!) |
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The band–band absorption process is also called the fundamental absorption process, it is described phenomenologically by Beer's
law: |
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The intensity I of the light at a depth z in the semiconductor,
I ( z ), is given by |
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I ( z ) |
= I0 · exp (– a · z)
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With I0 = intensity at z = 0 and a =
absorption coefficient of the material. |
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It is clear that a = a(hn)
is a strong function of the energy hn of the photons: |
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For hn < Eg(direct), no electron–hole
pairs can be created, the material is transparent and a is small. |
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For hn ³
Eg(direct), absorption should be strong. |
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All mechanisms other than the fundamental absorption may add complications (e.g. "sub
band gap absorption" through excitons), but usually are not very pronounced. |
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The absorption coefficients of major semiconductors indeed follow this predictions as can
be seen in the following diagram: |
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As expected, the absorption coefficient changes by 4 ... 5 orders of magnitude around
the band edge energy, and in direct semiconductors this change is "harder" than in indirect semiconductors. |
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Note that the absorption edge of Ge shows the features of both an indirect and a direct
transition, the latter one occurring only slightly higher in energy than the former. This is fully consistent with the band
structure of germanium (cf., e.g., here). |
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There are many more points to the absorption of light in semiconductors, but we
will not pursue the issue further at this point. |
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The optical efficiency hopt |
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If
we now look at an LED, we notice that light with wavelengths corresponding to the absorption edge thus will be
absorbed within a few µm of the material – and that automatically applies to
the light emitted by radiative recombination . |
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If we look at a naive cross section of a light emitting diode (on the left),
we see that only light from the edges of the p–n junction has a chance to make it to the surface of the device.
Obviously, this is not a good solution for a large optical efficiency. |
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If we make a junction more like in an integrated Si circuit (above right), the situation
is somewhat improved, but it might be difficult to drive high currents in the central region of the device, far away from
the contacts. |
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We might be better off in choosing an n-type material with a larger bandgap than the p-type
material and see to it that light is generated in the p-type material. Its photon energy then would be too small
for absorption in the large bandgap material and it could escape without absorption. In other words: We utilize a heterojunction (see below for details). |
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This sequence demonstrates several important points about the realization of LEDs: |
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1. A large optical efficiency is not
easy to achieve. Generally, much of the light produced will never leave the device. |
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2. The typical structures from Si
integrated circuit technology may or may not be useful for optoelectronic applications. In general, we have to develop
new approaches. |
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3.
We always should try to produce the light close to the (possibly internal) surface of the active material.
In other words, we need a defined recombination zone that is not deep in the
bulk of the active material. |
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4.
Heterostructures – meaning the combination of different semiconductors –
come up quickly in optoelectronics (while virtually unknown in Si technology – except for high-efficiency solar
cells). |
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Next, let's assume that the photons make it to the surface of the device. The
question now is if they are reflected back into the interior or if they can escape to the outside world. |
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This is a question that can be answered by basic
optics. The relevant quantities are shown in the next picture. |
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For the light beams coming from the interior of the semiconductor to the interface (air in
the picture; more generally a medium with a refractive index n2), Snellius'
law is valid: |
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n1 · sin Q1 |
= |
n2 · sin Q2 |
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With n1 = index of refraction of the semiconductor, n2
= index of refraction of the outside (= 1 if it is air). |
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Since relevant semiconductors have rather large refractive indexes (simply given by the square root of the dielectric constant), refraction
is quite severe. |
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As soon as Q2 reaches 90°, light will
be reflected back into the semiconductor; this happen for all angles Q1 larger
than Qcrit, the critical angle for total reflection, which is obviously given
by |
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For typical refractive indices of 3.5 (or dielectric
constants er
= 12.25), we have Qcrit = 17°. This is a severe limitation of hopt: Assuming that radiation is produced isotropically, a cone of 17° contains
only about 2% of the radiation! |
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But the situation is even worse
because photons within the critical angle may still become reflected – the probability is < 1, but not zero.
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For the transmissivity T, the fraction of light
that does not get reflected, the following relation (a variant of the general Fresnel
laws of optics) holds: |
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T = 1 – |
æ ç è |
n1 · cosQ
1 – n2 · cosQ2
n1 · cosQ1 + n2 · cosQ2 |
ö ÷ ø |
2 |
= 1 – R |
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With R = reflectivity = {intensity of reflected
beam} / {intensity of incoming beam}. |
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This can be simplified to an expression for the total fraction of light leaving
the semiconductor: |
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Ttotal |
» |
4 · n1 · n2
(n1 + n2)2 |
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For n1
» 3.5 and n2 = 1 (air) we have Ttotal
= 0.69, so only about 2/3 of the radiation contained within the critical angle leaves the semiconductor. |
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The total optical efficiency of LEDs with isotropic
generation of radiation thus is in the 1% region – something we must worry about! |
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The simplest solution is to "grade " the refractive
index, i.e. to lower it in steps. This is most easily achieved with a "drop" of epoxy or some other polymer. How
this method of index grading works becomes clear from the drawing: |
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Two light rays at the edge of some aperture have been traced; the relevant angles are shown
as pink triangles for the red light beam. The critical angle for total reflection at both interfaces is now considerably
larger. Note that the angle in the lower index medium is always larger and that this leads to a certain, not necessarily
isotropic radiation characteristics of the system. |
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The polymer layer, in other words, acts as an optical system – and by giving it specific
shapes we can influence the radiation characteristics to some extent. |
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In total, we see that getting the light out of the device (and having it more
or less focussed or otherwise influenced in its directional characteristics), is a major part
of optoelectronic technology. |
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In fact, a totally new field of research with some bearing to these problems has recently
be opened by the (first theoretical, and then experimental) "discovery" of so-called photonic
crystals – activate the link for some details. |
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© H. Föll (Semiconductors - Script)