1.5 Component representation of linear operators

Each operator can be defined in an abstract way by,

 \begin{equation*} y = A x \qquad , \end{equation*}(1.32)

e.g.

For using this operator in calculations, we have to define, how this operator acts on each vector \(x\). Taking the component representation of \(x\) and \(y\)

 \begin{equation*} x = \sum_i x_i |e_i\rangle \qquad \mbox{and} \qquad y = \sum_i y_i |e_i\rangle \end{equation*}(1.33)

we find

 \begin{equation*} y = \sum_i y_i |e_i\rangle = A x = \sum_i x_i A |e_i\rangle \qquad . \end{equation*}(1.34)

Multiplication with the Bra-vector leads to

 \begin{equation*} y_j = \sum_i \langle e_j| y_i |e_i\rangle \sum_i \langle e_j| A |e_i\rangle x_i \qquad . \end{equation*}(1.35)

Example:
Choosing the vector space of square integrable functions, the set of functions \(e^{ikx}\) serves as an orthonormal basis. Every vector (function) \(f\) may be represented as components of the functions \(e^{ikx}\). This is the Fourier-Analysis (Fourier-Transformation) of the function \(f\). The result of an operator \(A\) on a square integrable function is thus defined, when the components \(m_{i,j} = \langle e_j| A |e_i\rangle \) are known.
All results, proofed here for matrixes, are valid for linear operators as well.
REMARKS:


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© J. Carstensen (Quantum Mech.)