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Lets quickly recount the
essentials: |
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The concentrations of electrons or holes in the
conduction or valence bands are |
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ne |
= |
Neff ·
f(EC,EF,T) |
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nh+ |
= |
Neff · [1
f(EV,EF,T)] |
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The density of states for the donors and
acceptors is simply their concentration ND and
NA, we thus have : |
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Concentration of non-ionized
(neutral) donors NDo (i.e. the electron is
still sitting on the donor level) |
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Concentration of ionized donors
ND+ (i.e. the electron is in the conduction
band). |
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ND+ |
= |
ND · [1
f(E,EF,T)] |
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Concentration of ionized acceptors
NA (i.e. an electron from the valence
band is sitting on the acceptor level):. |
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Finally, the concentration of
neutral acceptors NA0; it is |
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NAo |
= |
NA · [1
f(EA,EF,T)] |
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This can be easily
envisioned in a simple drawing |
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The Fermi energy results from
equating the sum of all negative charges with the sum of all positive
charges. |
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The resulting equation is easily written down,
but cannot be solved analytically. |
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That is why we do it numerically. |
© H. Föll (Semiconductor - Script)